Question
Oxidation states of P in H4P2O5, H4P2O6, H4P2O7, are respectively
-
+3, +5, +4
-
+5, +3, +4
-
+5, +4,+3
-
+3, +4, +5
Solution
D.
+3, +4, +5
Oxidation state of H is +1 and that of O is -2
Let the oxidation state of P in the given compound x.
In H4P2O5,
(+1) x 4 +2 X x + (-2) x 5 = 0
4 + 2x -10 = 0
2x = 6
x = 3
In H4P2O6,
(+1) X 4 + 2 X x + (-2) x6 = 0
4 x + 2x-12 = 0
2x = 8
x =4
In H4P2O7,
(+1) x 4 x 2 X x + (-2) x 7 = 0
4 + 2x -14 = 0
2x = 10
x = +5
Thus oxidation states of P in H4P2O5, H4P2O6, H4P2O7, are +3, +4 and +5.
