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Solutions

Question
CBSEENCH12011277

A solution of sucrose (molar mass = 342 g mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be (kf for water = 1.86 K kg mol-1)


  • -0.372o C

  • -0.520o C

  • +0.372o C

  • -0.570o C

Solution

A.

-0.372o C

Depression in freezing point,

increment straight T subscript straight f space equals straight k subscript straight f space straight x space straight m

where comma space straight m space equals space molality space equals space fraction numerator straight w subscript straight B space straight x space 1000 over denominator straight M subscript straight B. space straight W subscript straight A end fraction

fraction numerator 68.5 space straight x space 1000 over denominator 342 space straight x space 1000 end fraction space equals space fraction numerator 68.5 over denominator 342 end fraction

increment straight T subscript straight f space equals space 1.86 space straight x space fraction numerator 68.5 over denominator 342 end fraction

space equals space 0.372 to the power of straight o straight C

increment straight T subscript straight f space equals space straight T to the power of straight o space minus space straight T subscript straight s
space equals space 0 space minus space 0.372 to the power of straight o straight C
equals negative 0.372 to the power of straight o straight C