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Electrochemistry

Question
CBSEENCH12011117

A button cell used in watches functions as following
Zn space left parenthesis straight s right parenthesis space plus Ag subscript 2 straight O space left parenthesis straight s right parenthesis space plus straight H subscript 2 straight O space left parenthesis straight l right parenthesis space rightwards harpoon over leftwards harpoon space 2 space Ag space left parenthesis straight s right parenthesis space plus Zn to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 OH to the power of minus space left parenthesis aq right parenthesis
If space half minus cell space potentials space are
Zn to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 straight e to the power of minus space rightwards arrow space Zn left parenthesis straight s right parenthesis semicolon space straight E to the power of 0 equals space minus 0.76 space straight V
Ag subscript 2 straight O space left parenthesis straight s right parenthesis space plus straight H subscript 2 straight O space left parenthesis straight l right parenthesis space plus 2 straight e to the power of minus rightwards arrow 2 Ag space left parenthesis straight s right parenthesis space plus 2 OH to the power of minus space left parenthesis aq right parenthesis space left parenthesis straight E to the power of 0 space equals space 0.34 space straight V right parenthesis
The cell potential will be

  • 1.10 V

  • 0.42 V

  • 0.84 V

  • 1.34 V

Solution

A.

1.10 V

Anode is always the site of oxidation thus anode half cell is 
Zn2+ (aq) +2e- --> Zn (s); E0 =-0.76 V
Cathode half cell is 
Ag2O (s) +H2O (l) +2e- ---> 2Ag(s) +2OH- (aq); E0 =0.34 V
E0cell = E0cathode -E0anode 
 = 0.34 -(-0.76) = +1.10 V