Question
Molar conductivities (Λom) at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S Cm2 mol-1 respectively. Λom for CH3COOH will be
-
425.5 S cm2 mol-1
-
180.5 S cm2 mol-1
-
290.8 S cm2 mol-1
-
390.5 S cm2 mol-1
Solution
D.
390.5 S cm2 mol-1
CH3COONa +HCl → NaCl + CH3COOH
91 + 425.9 = 126.4 + x
x= 516.9 -126.4
= 390.5 S cm2 mol-1