Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statements is incorrect for this reaction?
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Cu2I2 is reduced
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Evolved I2 is reduced
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Na2S2O3 is oxidized
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CuI2 is formed
D.
CuI2 is formed
CuSO4 + 2KI → Cul2 + I2
Thus Cul2 is not formed.