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Electrochemistry

Question
CBSEENCH12010944
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The limiting molar conductivities Λ° for NaCl, KBr and KCl are 126, 152 and 150 S cm2 mol-1 respectively. The Λ° for NaBr is

  • 128 S cm2 mol-1

  • 302 S cm2 mol-1

  • 278 S cm2 mol-1

  • 176 S cm2 mol-1

Solution

A.

128 S cm2 mol-1

By Kohlrausch's law
straight capital lambda subscript NaBr superscript straight o space equals space straight capital lambda subscript NaCl superscript straight o space plus space straight capital lambda subscript kBr superscript straight o space minus straight capital lambda subscript KCl superscript straight o space equals space 126 space plus space 152 minus 150 space equals space 128 space space straight s space cm squared space mol to the power of negative 1 end exponent

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