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Solutions

Question
CBSEENCH12010933

To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3PO3), the volume of 0.1 M aqueous KOH solution required is

  • 10 mL

  • 60 mL

  • 40 mL

  • 20 mL

Solution

C.

40 mL

H3PO3 is a dibasic acid (containing two ionizable protons attached to O directly) 
H3PO3 ⇌ 2H+ + HPO42-
0.1 M H3PO3  = 0.2 N H3PO3
0.1 M KOH = 0.1 N KOH
N1V1 = N2V2
(KOH) = (H3PO3)
0.1 V1 = 0.2 x 20
V1 = 40 mL