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Electrochemistry

Question
CBSEENCH12010867
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Given the data at 25oC,
Ag + I- → Agl +e-; Eo = 0.152 V
Ag → Ag+ + e- ;Eo = -0.800 V
What is the value of log Ksp for Agl?
(2.303RT/F = 0.059 V)

  • –8.12

  • +8.612

  • –37.83

  • -16.13

Solution

D.

-16.13

Agl space left parenthesis straight s right parenthesis space plus space straight e to the power of minus space rightwards harpoon over leftwards harpoon with space space space space space space space on top space Ag left parenthesis straight s right parenthesis space space plus space straight I to the power of minus space semicolon space straight E to the power of straight o equals space minus space 0.152 Ag space left parenthesis straight s right parenthesis space rightwards arrow with space space space space space space on top space Ag to the power of plus space plus straight e to the power of minus space semicolon space space space space space space space space space space space space space space straight E to the power of 0 space equals space minus 0.8 _________________________________________ AgI space left parenthesis straight s right parenthesis space rightwards arrow with space space space space space space space on top space Ag to the power of plus space plus space straight I to the power of minus space semicolon space space space space space space space space space space straight E to the power of 0 space equals space minus 0.952 straight E subscript cell superscript 0 space equals space fraction numerator 0.059 over denominator straight n end fraction space log space straight K minus 0.952 space equals space fraction numerator 0.059 over denominator 1 end fraction space log space straight K subscript sp log space straight K subscript sp space equals space minus fraction numerator 0.952 over denominator 0.059 end fraction space equals space minus space 16.135

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