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Electrochemistry

Question
CBSEENCH12010857
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The molar conductivities ∧oNaOAc and ∧o HCl at infinite dilution in water at 25o C are 91.0 and 426.2 S cm2 /mol respectively. To calculate ∧o HOAc, the additional value required is

  • ∧oH2O

  • ∧oKCl

  • ∧oNaOH

  • ∧oNaCl

Solution

D.

∧oNaCl

straight lambda subscript CH subscript 3 COONa end subscript superscript 0 space equals space straight lambda subscript CH subscript 3 COO to the power of minus end subscript superscript straight o space plus straight lambda subscript Na to the power of plus end subscript superscript 0 space...... space left parenthesis 1 right parenthesis straight lambda subscript HCl superscript 0 space equals space straight lambda subscript straight H to the power of plus end subscript superscript 0 space plus straight lambda subscript Cl to the power of minus end subscript superscript 0 space............ space left parenthesis 2 right parenthesis straight lambda subscript NaCl superscript 0 space space equals space straight lambda subscript Na superscript 0 space plus space straight lambda subscript Cl to the power of minus end subscript superscript 0 space........... left parenthesis 3 right parenthesis straight lambda subscript CH subscript 3 COOCH subscript 3 end subscript superscript 0 space equals space left parenthesis 1 right parenthesis space plus left parenthesis 2 right parenthesis space minus space left parenthesis 3 right parenthesis

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