The molar conductivities ∧^oNaOAc and ∧^o HCl at infinite dilution in water at 25^o C are 91.0 and 426.2 S cm² /mol respectively. To calculate ∧^o HOAc, the additional value required is

∧^oH₂O

∧^oKCl

∧^oNaOH

∧^oNaCl

Solution

∧^oNaCl

straight lambda subscript CH subscript 3 COONa end subscript superscript 0 space equals space straight lambda subscript CH subscript 3 COO to the power of minus end subscript superscript straight o space plus straight lambda subscript Na to the power of plus end subscript superscript 0 space...... space left parenthesis 1 right parenthesis straight lambda subscript HCl superscript 0 space equals space straight lambda subscript straight H to the power of plus end subscript superscript 0 space plus straight lambda subscript Cl to the power of minus end subscript superscript 0 space............ space left parenthesis 2 right parenthesis straight lambda subscript NaCl superscript 0 space space equals space straight lambda subscript Na superscript 0 space plus space straight lambda subscript Cl to the power of minus end subscript superscript 0 space........... left parenthesis 3 right parenthesis straight lambda subscript CH subscript 3 COOCH subscript 3 end subscript superscript 0 space equals space left parenthesis 1 right parenthesis space plus left parenthesis 2 right parenthesis space minus space left parenthesis 3 right parenthesis

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