-->

Solutions

Question
CBSEENCH12010826

A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60 g mol–1) in the same solvent. If the densities of both the solutions are assumed to be equal to 1.0 gcm–3, molar mass of the substance will be –

  • 90.0g mol–1

  • 115.0g mol–1

  • 105.0g mol–1

  • 210.0 g mol–1

Solution

D.

210.0 g mol–1

Solutions with the same osmotic pressure are isotonic
Let the molar mass of the substance be M

π1 =C1RT=C2RT =π2
So, C1 = C2
As density of the solutions are same
So comma space fraction numerator 5.25 over denominator straight M end fraction space equals space 15 over 60
straight M space equals space fraction numerator 5.25 space straight x space 60 over denominator 1.5 end fraction space equals space 210