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1 gram of a carbonate (M₂CO₃) on treatment with excess HCl produces 0.01186 mole of CO₂. The molar mass of M₂CO₃ in g mol^-1 is

1186

84.3

118.6

11.86

Solution

B.

84.3

Given chemical equation
M₂CO₃ +2HCl → 2MCl + H₂O + CO₂
1 gm 0.01186 mol
From the balanced chemical equation
1/M = 0.01186
M = 84.3 gm/mol

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