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Coordination Compounds

Question
CBSEENCH12010574
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Sc3+ is colourless in aqueous solution whereas Ti3+ is coloured.

Solution

Electronic configuration of Ti3+ is [Ar]3d2 4s2. Metal ions usually form hexacoordinated complexes with water molecules.  According to Crystal field theory [Ti(H2O)6]+3, Ti3+ ion has outer shell configuration ast2g1eg0 There is an electron free to jump between energy level. Thus Ti3+ ions selectively absorb certain colours, hence its solution is coloured.

SC3+, on the other hand, has an empty d orbital; the [Sc(H2O)6]+3 complex has no electrons in T2g or eg orbitals. Hence SC3+ is colourless in aqueous solution.

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Dichloridobis(ethane-1, 2-diamine)platinum(lV) nitrate.

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

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