The p-Block Elements

The p-Block Elements

Question

Give reasons:
i) SO2 is reducing while TeO2 is an oxidizing agent.
ii) Nitrogen does not form pentahalide.
iii) ICl is more reactive than I2

Answer

i) Sulphur dioxide is reducing agent because sulphur has d-orbital so it can easily expand its oxidation state +4 to +6 and thus behave as reducing agent.
in the case of TeO2, Te is a heavier element and due to inert pair effect, the Te does expand its oxidation state +4 to +6.

ii) The electronic state of Nitrogen is 1s2 2s2 2p3. Nitrogen does not have d orbital and due to the absence of d -orbital it does not form pentahalide.

iii) ICl is more reactive than I2 because I-Cl bond in ICl is weaker than I-I bond in I2.

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