Electrochemistry

  • Question
    CBSEENCH12010485

    Calculate the degree of dissociation (a) of acetic acid if its molar conductivity (Λm) is 39.05 S cm2mol–1. Given λo(H+) = 349.6 S cm2 mol–1 and λo(CH3COO) = 40.9 S cm2 mol–1

    Solution

    The degree of dissociation is given by,
    α = Λm / λo

    here, α is the degree of dissociation,
    Λm is the molar conductivity
    λo is the molar conductivity at infinite dilution.

    We have given
    λo(H+) = 349.6 S cm2mol-1
    and
    λ0(CH3COO-) = 40.9 S cm2mol-1
    then,

    λoCH3COOH = λo CH3COO-+ λoH+

    λoCH3COOH = 349.6 + 40.9 = 390.5

    Now, degree of dissociation (α),
    α = Λmo
    = 39.05 / 390.5 = 0.1

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