Electrochemistry

Electrochemistry

Question

The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9S cm2mol-1. Calculate the conductivity of the conductivity of this solution.

Answer
Molar space conductivity comma space straight k equals space conductivity over Concentration

straight capital lambda subscript straight m space equals straight k over straight c

conductivity comma

straight k equals space straight capital lambda subscript straight m space equals straight k over straight c

conductivity comma space straight k equals space straight capital lambda subscript straight m space straight x space straight C

equals space fraction numerator 138.9 space left parenthesis Scm squared space mol to the power of negative 1 end exponent right parenthesis space straight x space 1.5 space left parenthesis mol divided by straight L right parenthesis over denominator 1000 space left parenthesis cm cubed divided by straight L right parenthesis end fraction space equals 0.208 space straight S space cm to the power of negative 1 end exponent

More Chapters from Electrochemistry