Question
Calculate the freezing point of the solution when 31 g of ethylene glycol (C2H6O2) is dissolved in 500 g of water. (Kf for water = 1.86 K kg mol–1)
Solution
The freezing point of pure water is 273.15 K. On dissolving ethylene glycol, freezing point, being a colligative property, will be lowered.
We are given that
Kf for water =1.86 K kg mol-1
Mass of solute, ws = 37 g
Molar mass of solute, Ms = 12 x 2 + 1 x 6 + 16 x 2
= 62 g mol-1
Mass of water, W = 500 g
Therefore
Hence, the freezing point of the solution, Tf = 273.15K – 1.86 K
= 271.29 K