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Solutions

Question
CBSEENCH12010276

Calculate the freezing point of the solution when 31 g of ethylene glycol (C2H6O2) is dissolved in 500 g of water. (Kf for water = 1.86 K kg mol–1)

Solution

The freezing point of pure water is 273.15 K. On dissolving ethylene glycol, freezing point, being a colligative property, will be lowered.

  increment straight T subscript straight f space equals fraction numerator space straight K subscript straight f space straight x space straight w subscript straight s space straight x space 1000 over denominator straight M subscript straight s straight x space straight W end fraction

We are given that

Kf for water =1.86 K kg mol-1

Mass of solute, ws = 37 g

Molar mass of solute, Ms = 12 x 2 + 1 x 6 + 16 x 2

                                         = 62 g mol-1

Mass of water, W = 500 g

Therefore   increment straight T subscript straight f space equals space fraction numerator 1.86 space straight x space 31 space straight x space 1000 over denominator 62 space straight x space 500 end fraction space equals space 1.86 space straight K

Hence, the freezing point of the solution, Tf = 273.15K – 1.86 K

                                                                          = 271.29 K