The conductivity of 0.20 M solution of KC l at 298 K is 0.025 S cm - 1 . Calculate its molar conductivity? - Wired Faculty

Electrochemistry

Question

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm^-¹. Calculate its molar conductivity?

Solution

straight k left parenthesis straight S space cm to the power of negative 1 end exponent right parenthesis space equals space 0.025 space straight S space cm to the power of negative 1 end exponent Molarity space left parenthesis mol space straight L to the power of negative 1 end exponent right parenthesis space equals space 0.20 space straight M Molar space conductivity space left parenthesis straight capital lambda subscript straight m space right parenthesis equals space fraction numerator straight K over denominator 1000 space straight x space molarity end fraction space equals fraction numerator 0.025 over denominator 1000 space straight x space 0.20 end fraction space equals space 1.25 space straight x space 10 to the power of negative 4 end exponent space straight S space cm squared space mol to the power of negative 1 end exponent

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