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Solutions

Question
CBSEENCH12010067

3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1.62 K. Calculate the van't Hoff factor and predict the nature of solute (associated or dissociated).


(Given: Molar mass of benzoic acid = 122 g mol-1, Kf for benzene = 4.9 K kg mol-1

Solution

We know that the depression in freezing point is given by
increment straight T subscript straight f space equals fraction numerator ik subscript straight f space straight x space straight w subscript straight s space straight x space 1000 over denominator straight M subscript straight s space straight x space straight W end fraction

 Here     

 Depression in freezing point K

 Kf for benzene=4.9kg mol-1

 Mass of benzene W=49g

 Molar mass of benzoic acid ms = 122g mol-1

 Substituting the value we get

 

1.62 = 1.62 space equals fraction numerator straight i space straight x space 4.9 space straight x space 3.9 space straight x space 1000 over denominator 122 space straight x 49 end fraction

i space equals space fraction numerator 1.62 space x space 122 space x space 49 over denominator 4.9 space x space 3.9 space x space 1000 end fraction space equals 0.51
As the value of i<1 benzoic acid is associated solute.