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Aldehydes, Ketones And Carboxylic Acids

Question
CBSEENCH12008696

Explain haloform reaction.

Solution

Methyl Ketones CH3COR on oxidation with X2/NaOH (X = Cl, Br, I) gives sodium salt of carboxylic acid with one carbon atom less. The CH3 group bonded to carbonyl group is converted to haloform, CHX3'. With iodine in NaOH, a yellow precipitate of iodoform CHI3 is obtained (iodoform test).