Sponsor Area

Electrochemistry

Question
CBSEENCH12006135

Calculate ΔG° for the reaction                   Cu2+(aq)+Fe(s)  Fe2+(aq) + Cu(s)(Given E°Cu2+/Cu = 0.34 V,   E°Fe3+/Fe = -0.44 V,  F = 96500 e mol-1)

Solution
E°cell = E°cathode - E°anode = E°Cu2+/Cu - E°Fe3+/Fe           = 0.34 V - (-0.44 V) = 0.78 V   rG = -nFE°             = -2  × 96500 × 0.78                                 (   n = 2)              = -150540 J = -150.54 kJ