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Electrochemistry

Question
CBSEENCH12006124
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A solution of CuSO4 is electrolysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?

Solution

t = 600 s
Charge = current x time
= 1.5 A x 600s = 900 C
According to the reaction : Cu2+(aq) + 2e– → Cu(s)
We require 2F or 2 x 96487 C to deposit 1 mol or 63 g of Cu
For 900 C, the mass of Cu deposited  = (63 g mol-1 × 900 C)2 × 96487 C mol-1 = 0.2938 g.

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