Question
The conductivity of 0.00241 M acetic acid is 7.896 x 10–5 s cm–1. Calculate its molar conductivity and if Λ°m for acetic acid is 390.5 s cm2 mol–1, what is its dissociation constant?
Solution
M = 0.00241 M
K = 7.896 x 10-5 s cm-1