Question
The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K. is 1.46 x 10–6 s cm–1.
Solution
We ave given that
R = 1500 Ω
K = 1.46 x 10–4 Ω–1 cm–1
Cell constant = K x R
= 1.46 x 10–4 x 1500 = 0.219
