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Electrochemistry

Question
CBSEENCH12006108

The standard reduction potential of the reaction at 25°C
2H2O + 2e H2(g) + 2OH is – 0.8277 V
Calculate equilibrium constant for the reaction
2H2O H3O++OH- at 25°C.

Solution

Consider the given reaction as the net cell reaction 
two half reaction :

Oxidation:
H2O +1/2H2 ----> H3O+ +e-  Ecell0 =0


reduction: 
H2O +e- -----> 1/2H2(g) + OH- Ecell0 = -0.8277V

It is evident from the cell reaction that it involves the transfer of one electron so that n= 1
logKc =nEcell00.059Kc = antilog 10.059(-0.8277) =--14.028 = 15.972Kc =Antilog (15.972)  =9.376×10-15

 9.88 × 10-15