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Electrochemistry

Question
CBSEENCH12006104

Calculate the equilibrium constant of reaction at 25°C:
Ni(s) + Cu2+ (aq) → Cu(s) + Ni2+ (aq)
Given : E°Ni2+/Ni = -0.25 V, E°Cu2+/Cu = + 0.34 V, R = 8.314 J K–1 mol–1, F = 96500 C mol–1.

Solution

We have given 
 E°Ni2+/Ni = -0.25 V
Cu2+/Cu = + 0.34 V,

Ecell
0 =Ecell0 =ECu2+Cu0 - ENi2+Ni0  


Ecell0 =
0.34-(-0.25) 

Ecell0 
= 0.34+0.25 =0.59

R = 8.314 J K–1 mol–1
F = 96500 C mol–1.
T=25celcius =273+25 =298 Kelvin
n= 2 
K =Antilog nFEcell02.303×R×T



 

 

K =Antilog 2×96500×0.592.303×8.314×298



= Antilog[19.956]

Ans.  9.07 x 1019