Question
Calculate the equilibrium constant of reaction at 25°C:
Ni(s) + Cu2+ (aq) → Cu(s) + Ni2+ (aq)
Given : E°Ni2+/Ni = -0.25 V, E°Cu2+/Cu = + 0.34 V, R = 8.314 J K–1 mol–1, F = 96500 C mol–1.
Solution
We have given
E°Ni2+/Ni = -0.25 V
E°Cu2+/Cu = + 0.34 V,
Ecell0 =
= 0.34-(-0.25)
= 0.34+0.25 =0.59
R = 8.314 J K–1 mol–1
F = 96500 C mol–1.
T=25celcius =273+25 =298 Kelvin
n= 2
= Antilog[19.956]
Ans. 9.07 x 1019