Question
When a current of 0.75 A is passed through a CuSO4 solution for 25 min, .36 g of copper is deposited at the cathode. Calculate the atomic mass of copper.
Solution
Time = 25 min = 25 x 60 sec
Current = 0.75 A
Electricity passed = 25 x 60 x 0.75 = 1125 C of electricity deposit copper = 0.369 g. 2 x 96500 C
of electricity will deposit copper.
M= ZxIxT
Atomic mass of copper = 63.3 u.