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Electrochemistry

Question
CBSEENCH12006007

In a fuel cell, H2 and O2 react to produce electricity. In the process H2 gas is oxidised at the anode and O2 at cathode. If 67.2 litre of H2 at STP reacts in 15 minutes, what is the average current produced? If the entire current is used for electro-deposition of Cu from Cu2+, how many grams of copper are deposited?

Solution
The redox changes in fuel cell are
               2H2(g) + O2(g)   2H2O (l)
At anode:     H2+2OH-    2H2O + 2e
At cathode:  O2+2H2O+4e   4OH-
Therefore, moles of H2 reacting = 67.222.4 = 3

Therefore, equivalent of H2 used  = 67.222.4=3
Now,            wE= i×t96500
Therefore,        
                   6 = i×15×6096500i = 643.33 ampere
or
   Also Eq. of H2 = Eq. of Cu formed  = 6.
Hence,           WCu = 6×63.52=190.5 g.