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Electrochemistry

Question
CBSEENCH12006088

For the standard cell, Cu(s) | Cu2+(aq) || Ag+ (aq) | Ag(s)
Given: E° Cu2+/Cu = 0.34V, E° = 0.80V
(a) Identify cathode and anode as the current is drawn through the cell.
(b) Write the reactions taking place at the electrodes.
(c) Calculate the standard cell potential.

Solution

a)ECu2+Cu0 <EAg+Ag0Therefore copper electorode isthe anode and silverelectrode act as a cathode. The half reaction are:anode: Cu(s) Cu2+ +2e-Cathode: 2Ag+ +2e- 2Agb) net reaction :Cu(s) +2Ag+(aq) Cu2+(aq) +2Ag(s)c) The potential of the cell is given by E =Ecell0 -0.059nlog[Cu2+][Ag+]20 =(+0.80-0.34) -0.0592log0.01[Ag+]2 log0.01(Ag+)2+ = 2 x 0.460.059 =15.593taking antilog 0.01[Ag+]2 =antilog 15.593 =3.919 x 1015[Ag+]2 =0.013.919 x1015 =2.55 x10-18[Ag+] =1.59 x 10-9M