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Electrochemistry

Question
CBSEENCH12005999

 The half reactions are:
(i) Fe3+ + e → Fe2+, E° = 0.76 V
(ii) Ag++ e → Ag,E° = 0.80 V
Calculate Kc for the following reaction at 25° C:
     Ag++Fe3+    Fe3++Ag                                    (F = 96500 C mol-1)

Solution
E°cell = E°Ag+/Ag-E°Fe3+/Fe2+           = + 0.80 V - 0.76 V = + 0.04 V   + nE°F = 2.303 RT log k      log K = 0.040.0591 0.6779          K =  4.763.