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Electrochemistry

Question
CBSEENCH12005988

Silver is electrodeposited on a metallic vessel of total surface area 900 cm2 by passing a current of 0.5 amp for two hours. Calculate the thickness of silver deposited. [Given : Density of silver = 10.5 g cm–3, Atomic mass of silver = 108 amu, F = 96,500 C mol–1]

Solution


m = Z x I x t
or          m= 10896500×0.5×2×60×60

or                 m= 108×5965×10×2×6×6 = 4.03 g     m = V × d   4.03 = V×10.6 g cm-3
or                      V = 4.0310.6  cm3 = 0.39 cm3V = area × thickness
or      0.39 cm3 = 900 cm2 × thickness
Thickness = 0.39 cm3900 cm2 = 4.33 × 10-4 cm