Question
Calculate the emf of the cell Zn/Zn2+ (0.1 M) || Cd2+ (0.01 M) | Cd at 298 k. (given)
E°Zn2+/Zn = – 0.76 V and E°Cd2+/Cd = – 0.40 V).
Solution
Zn/Zn2+(0.1 M) || Cd2+ (0.01) | Cd