Question
The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is 0.146 x 10–3 s cm–1.
Solution
Given that ,
Conductivity of the cell , κ = 0.146 × 10−3 S cm−1
Resistance of the cell , R = 1500 Ω
Formula of cell constant
Cell constant = κ × R
Plug the values we get
= 0.146 × 10−3 × 1500
= 0.219 cm−1
