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Electrochemistry

Question

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How much electricity is required in coulomb for the oxidation of
1 mol of FeO to Fe₂O₃

Solution

2 FeO + H_{2} O \to {Fe}_{2} O_{3} + 2 H^{+} + 2 e^{-} 2 mol 2 mol or 2 F (oxidation reaction)

Charge on Fe in compound FeO = + 2

Charge on Fe in compound Fe₂O₃= + 3

Change in charge n = 1

Electricity required = nF

= 96487 Coulombs

= 9.65 × 10⁴Coulombs

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