+91-8076753736 [email protected]

-->

Electrochemistry

Question

Wired Faculty App

How much charge is required for the following reductions:
1 mol of Cu²⁺ to Cu?

Solution

{Cu}^{2 +} + 2 e^{-} \to Cu 1 mol 2 mol 1 mol (reduction of {Cu}^{2 +} cathode)

Formula required charge n × F

n = difference of charge on ions

F is constant and equal to 96487 Coulombs

Here n = 2

plug the value in formula we get

Required charge= 2 × 96487 Coulombs

= 192974 Coulombs

= 1.93 × 10⁵ Coulombs

Some More Questions From Electrochemistry Chapter

Why does the conductivity of a solution decrease with dilution?

Suggest a way to determine the Λ°_m value of water.

The molar conductivity of 0.025 mol L^–1methanoic acid is 46.1 S cm² mol^–1. Calculate its degree of dissociation and dissociation constant. Give λ°(H⁺) = 349.6 S cm²mol^–1 and λ° (HCOO^– ) = 54.6 s cm² mol^–1.

If the current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons flow through the wire?

Suggest a list of metals that are extracted electrolytically.

Consider the reaction: Cr₂O₇^2– + 14H⁺ + 6e- → 2Cr³⁺ + 8H₂O
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr₂O₇^2-?

Write the chemistry of recharging the lead storage battery, highlighting all the materials that are involved during recharging.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation