Sponsor Area

Electrochemistry

Question
CBSEENCH12005965

Explain why electrolysis of aqueous solution of NaCl gives H2 at cathode and Cl2 at anode. Write overall reaction.

Solution
Sodium chloride and water ionize as follows:
NaCl Na+ + Cl-H2O H+ + OH-
At cathode: Both Na+ and H+ ions are present near the cathode. But the discharge potential of H+ is lower than that of Na+ ion. So H+ ions are discharged in preference to Na+ ions.
H+ +e-  HH + H  H2
Thus H2 gas is liberated at the cathode and Na+ ions remain in the solution.
At the anode: Both Cl and OH ions are present near the anode. As the discharge potential of Cl ions is lower than that of OH- ions, so Cl ions are discharged in presence to OH ions.

Cl- + e-  ClCl   + Cl   Cl2

Thus Cl
2 is liberated at anode and OH ions remain in the solution.
The overall reaction is:
NaCl(aq) + H2 O(l) → Na+ (aq) + OH– (aq)
+12H2(g)+12Cl2(g)