Question
Explain why electrolysis of aqueous solution of NaCl gives H2 at cathode and Cl2 at anode. Write overall reaction.
Solution
Sodium chloride and water ionize as follows:
At cathode: Both Na+ and H+ ions are present near the cathode. But the discharge potential of H+ is lower than that of Na+ ion. So H+ ions are discharged in preference to Na+ ions.
Thus H2 gas is liberated at the cathode and Na+ ions remain in the solution.
At the anode: Both Cl– and OH– ions are present near the anode. As the discharge potential of Cl– ions is lower than that of OH- ions, so Cl– ions are discharged in presence to OH– ions.
Thus Cl2 is liberated at anode and OH– ions remain in the solution.
The overall reaction is:
NaCl(aq) + H2 O(l) → Na+ (aq) + OH– (aq)
At cathode: Both Na+ and H+ ions are present near the cathode. But the discharge potential of H+ is lower than that of Na+ ion. So H+ ions are discharged in preference to Na+ ions.
Thus H2 gas is liberated at the cathode and Na+ ions remain in the solution.
At the anode: Both Cl– and OH– ions are present near the anode. As the discharge potential of Cl– ions is lower than that of OH- ions, so Cl– ions are discharged in presence to OH– ions.
Thus Cl2 is liberated at anode and OH– ions remain in the solution.
The overall reaction is:
NaCl(aq) + H2 O(l) → Na+ (aq) + OH– (aq)