Question
are -0.25 V and + 0.34 respectively at 298 K. Formulate the self operating galvanic cell for this electrode pair. What reaction takes place in its operation? How is the ΔG° for this reaction related to the cell e.m.f.?
Solution
The cell may be represented as:
we have given that
Relationship between and cell e.m.f.
here n=2
F=96500
E0cell= 0.59
plug in above equation we get
=-2 x 96500 x 0.59 =-113870 Kj/mol
we have given that
Relationship between and cell e.m.f.
here n=2
F=96500
E0cell= 0.59
plug in above equation we get
=-2 x 96500 x 0.59 =-113870 Kj/mol