Question
Given the two half cell reaction:
Anode: Cu(s) → Cu2+ (aq) + 2e–
Cathode: Ag+ (aq) + e– → Ag(s)
Write the galvanic cell for the net reaction.
Solution
Answer:
The net cell reaction is
Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s)
and the galvanic cell is
Cu(s) |Cu2+ (aq) || Ag+ (aq) | Ag(s)
The net cell reaction is
Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s)
and the galvanic cell is
Cu(s) |Cu2+ (aq) || Ag+ (aq) | Ag(s)
