Sponsor Area

Electrochemistry

Question
CBSEENCH12005845

The cell in which the following reaction occurs:
2Fe3+ (aq) + 2I(aq)  2Fe2+ (aq) + I2(s) has E0cell = 0.236 V at 298 K. Calculate the standerd Gibbs energy and the equilibrium constance of the cell reaction.

Solution

Answer:

The cell is
2Fe3+ (aq) + 2I(aq)   2Fe2+(aq)+I2(s)
E0 cell = 0.236 V0ar G0 =-nFE0cell            =-2×0.236×96487 C mol-1            = -45541 J            = -45.54 kJ mol-1

log Kc = nFE0cell2.303 × RT            = 2×96487×0.2362.303×8.31×298             = 45541.8645703.1031 = 7.9854or      Kc = Antilog 7.9854 or    Kc = 9.62 × 107