Question
Calculate the emf of the cell in which the following reaction takes place:
Ni(s) + 2Ag+ (0.002 M) Ni2+ (0.160 M) + 2Ag(s)
Given that
Solution
Answer:
or
The equation is also written as
or
or
The equation is also written as
or
= 1.05 V – 0.0295 x log 80
= 1.05 V – 0.0295 x 1.9031
= 1.05 V – 0.056 = 0.99 V.