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Electrochemistry

Question

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Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Solution

Answer:

For hydrogen electrode, ,

given that pH = 10

use formula [H⁺] = 10^–pH

so that [H⁺] = 10⁻¹⁰ M

Electrode reaction will

H⁺ + e^– →1/2 H₂

Use the formula

E_{H^{+} / H_{2}} = {E^{o}}_{H}^{+} / H_{2} - \frac{RT}{nF} \ln \frac{[H_{2}]}{[H^{+}]^{2}} = 0 - \frac{8.314 \times 298}{2 \times 96500} \ln \frac{[I]}{{[H^{+}]}^{2}} = 0.05915 \log [H^{+}] = - 0.05915 pH = - 0.05915 \times 10 = - 0.59 V

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