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The freezing point of a solution containing 0.2g of acetic acid in 20.0 g of benzene is lowered by 0.450C. calculate the degree of association of acetic acid in benzene. (Kf for benzene =5.12K kg mol-1)
Mass of CH3COOH =60g/molobserved molecular mass = Kf xWb x1000∆Tf x WA =5.12 x 0.2 x100020 x0.45 =113.8g mol-1Acetic acid associates as:2CH3COOH ⇋ (CH3COOH) 1 0 1-α α/2No . of particles after association = 1-α+α2 =1-α2We know that No. of particels after association No. of partcles before association =Normal molecular mass Observed molecular massor 1-(α/2)1 =60113.6solving α =0.945therefore degree of association =94.5%
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