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Solutions

Question
CBSEENCH12005829

Calculate the vapour- pressure lowering of water when5.67g of glucose, C6H12O6 is dissolved in 25.2 g water at 250C. The vapour pressure of water at 250C is 23.8 mmHg. What is the vapour pressure of the solution?

Solution

WB =5.67g

WA =25.2g

MB=180g/mol

MA=18g/mol

NB= 5.67/180 =0.0315 mol glucose

NA=25.2/18 =1.40 mol water

  mole fraction of glucose,xB =0.03151.40 +0.0315 =0.022we know that lowering of V.P = p0 -p p0xB =23.8 x0.022 =0524 mmHgp0-pp0 =xBp=pA0 -(p0-p) =23.8 -0.524 =23.3mm Hg