Question
At 300 K, 36 g of glucose present per litre in its solution has an osmotic pressure of 4.98 bar. If osmotic pressure of solution is 1.52 bar at the same temperature, what would be its concentration.
Solution
Answer:
Solution:
Mass of glucose, w =36 g
Osmotic pressure, π = 4.98 bar
Temperature, T = 300 K
Volume of solution, V = 1L
Formula of osmotic pressure
=
Plug the value and solve for R we get
R = π V/(nT) = 4.98 × 180/ (36 × 300)
R = 4.98/ 60 L atm K-1 mol– 1
Plug the value in second case we get
C = π/(RT)
Plug the values we get
C = 0.061 M
