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Solutions

Question
CBSEENCH12005826

Urea forms an ideal solution in water. Determine the vapour pressure of an aqueous solution contains 10% by mass of urea at 400C. (Vapour pressure of water at 400C = 55.3 mm of Hg)

Solution

Answer:

p°-pp° = xurea

Let the mass of solution be 100g 
 therefore mass of urea = 10 g
 molecular mass of urea = 60 g
 
xurea = 10/60 =1/6

molecular mass of water = 18g
xwater = 90/18 =5

xurea = mole fraction of urea total mole fraction of solutionxurea =1/61/6+5 = 1/631/6xurea = 1/31using above formula55.3-p55.3 = 13155.3-p = 55.331p= 55.3-55.33155.31-131 =pp =55.3 ×3031p= 53.52mm Hg