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Solutions

Question
CBSEENCH12005823

Urea forms an ideal solution in water. Determine the vapour pressure of an aqueous solution containing 10% by mass of urea at 400C. (Vapour pressure of water at 400C = 55.3 mm of Hg)

Solution

Answer:

by using formula .

p° -pp° = xurea

let the mass of solution be 100g
therefore mass of urea = 10g
molecular mass of urea = 60 g

xurea = 10/60 = 1/6

molecular mass of water = 18 g
 xwater = 90/18 = 5

mole fraction of urea =xurea =1/61/6+5 = 1/631/6xurea =1/31using above formula 55.3-p55.3 =13155.3- p = 55.33155.3- 55.331 = p55.31-131 =pp= 55.3 ×3031 =53.52mm Hg