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Solutions

Question
CBSEENCH12005738

Calculate the molarity of 1 litre solution of 93% H2SO4 (weight/volume). The density of solution is 1.84 gm L–1.

Solution

(i) Volume of solution = 1 L = 1000 mL
Density of solution = 1.84 g mL–1
Mass of solution = V x d
= (1000 mL) x 1.84 mL–1
= 18540 g
Mass of H2SO4 = 93g/100mL
 93 x 10 = 930 g
Mass of solvent (water)
= 1840 – 930 = 910 g.
(ii) Molarity (m)
   
   = Mass of H2SO4/Molar mass of H2SO4Mass of water in kg
  Mass of H2SO4                         = 930 g, Molar mass of H2SO4                        = 98 g mol-1Mass of water = 910 g1000 = 0.91 kg


Molarity (m) = 930g/98 mol-1(0.91 kg)                      = 10.43 mol kg-1 = 10.43 m.