Question
Heptane and octane form an ideal solution. At 373 K, the vapour pressures of the two liquid components are 105.2 kPa and 46.8 kPa respectively. What will be the vapour pressure, in bar of a mixture of 26.0 g of heptane and 35.0 g of octane?
Solution
Answer:
We have given,
Molar mass of heptane,
C7H16 = 100 g mol–1
Molar mass of octane,
C8H18 = 114 g mol–1
Moles of heptane
Similarly, Moles of octane
Mole fraction heptane
Mole fraction of octane
Partial vapour pressure = Mole fraction x Vap.
Pressure of pure component.
Partial vapour pressure of heptane
= 0.456 x 105.2 = 47.97 kPa
Partial vapour pressure of octane
= 0.543 x 46.8 = 25.4 kPa
Total vapour pressure of solution = 73.08 kPa.