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Solutions

Question
CBSEENCH12005725

A solution of glucose in water is labelled as 10% W/W, what would be the molality and mole fraction of each component in the solution? If the density of the solution is 1.2 g mL–1, then what shall be the molarity of the solution? 

Solution

Consider 100 g of 10% solution of glucose whose conc. is 10% W / W.
Mass of solution = 100 g
Mass of glucose = 10 g
Mass of solvent = 100 – 10 = 90 g
Molar mass of glucose,
C6H12O6 = 6 x 12 + 12 x 1 + 6 x 16
= 72 + 12 + 96 = 180 g / mol

Molality = Mass of soluteMolar mass of solute×1Mass of solvent in kg
            = 10180×0.09 kg = 0.617 m.

     Moles of H2O, nA = 9018 = 5
           Moles of glucose, nB = 10180 = 0.055
                      0.0555+0.055 = 0.0108 = .01
Mole fraction of glucose, xB = nBnA+nB
Mole fraction of water
            xA = 1-xb = 1-0.0108 = 0.989 = 0.99
                       Density of sol = 1.2 g mol L
Therefore, volume of solution
                 = MassDensity  = 1001.2 = 83.33 mL

                  Molarity  = 10/18083.33/100=0.67