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Question
CBSEENCH12005612

What is expected value of Van’t Hoff factor for K3 [Fe(CN)6] in dilute solution?

Solution
solution:
The dissociative equation for K3[Fe(CN6)] can be written as:

 k3 Fe(CN)6  3K++[Fe(CN)6]3-
 
therefore , number of particles after dissiociation = 4
so van't hoff factor =4/1 = 4