Question
Henry’s law constant for CO2 in water is 1.67 x 108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.
Solution
Solution :
given that,
pressure of CO2=2.5atm
1 atm = 1.01325x 105 pa so that
pressure of CO2 = 2.5x1.01325x105pa
= 2.533125 x 105 pa
KH = 1.67 x 108 pa
ACcording to henry's law p= KH*X
or X=P/KH
= 2.533125 x 105/1.67x 108
= 1.52 x 10-3
But we have 500ML odf soda water so that
Volume of water = 500mL
Density of water =1g/ml
mass = volume x density
500 mL of water = 500g of water
molar mass f water (H2O) = 18g mol-1
number of moles =