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Solutions

Question
CBSEENCH12005602

Henry’s law constant for CO2 in water is 1.67 x 108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.

Solution

Solution :
given that, 
pressure of CO2=2.5atm
1 atm = 1.01325x 105 pa  so that 
pressure of CO2 = 2.5x1.01325x105pa
   = 2.533125 x 10pa
KH = 1.67 x 10pa
ACcording to henry's law  p= KH*X
or X=P/KH 
     = 2.533125 x 105/1.67x 108
     = 1.52 x 10-3

But we have 500ML odf soda water so that 
Volume of water = 500mL
Density of water =1g/ml
mass = volume x density 
500 mL of water = 500g of water
molar mass f water (H2O) = 18g mol-1
number of moles =MassMolar massNumber  of mole of water =5018  = 27.78 mol of waternow use the formula of mole fraction x= nCO2nCO2+nH2OValue of mole fraction is very small so it is negligibleas compared to 1x nCO2nH2OnCO2 = 27.78×1.52×10-3molar mass of CO2 =12+2×16=44 g mol-1use formula mass = molar mass× number of moles            = 0.042×44             =1.848g